Aaah! Kattis Problem Solution In Java

// Nayeem Shahriar Joy , Applied Physics & Electronic Engineering , University of Rajshahi.

import java.util.Scanner;

public class Joy {

public static void main(String[] args) {

String s1,s2;

Scanner sc1=new Scanner(System.in);

s1=sc1.nextLine();

s2=sc1.nextLine();

int able=s1.length();

int say=s2.length();

if(able>=say)

{

System.out.print("go");

}

else

{

System.out.print("no");

}

}

}

Seven Wonders Kattis Problem Solution In Java

//Nayeem Shahriar Joy,Applied Physics & Electronic Engineering, University of Rajshahi.

import java.util.HashSet;

import java.util.Scanner;

import java.util.Set;

public class Joy{

public static void main(String[] args) {

Scanner io = new Scanner(System.in);

String s=io.nextLine();

long ans=0;

int C=0,T=0,G=0;

for(int i=0;i<s.length();i++)

{

char c=s.charAt(i);

if(c=='T')

{

T++;

}

else if(c=='G')

{

G++;

}

else if(c=='C')

{

C++;

}

}

int seven=Math.min(T, Math.min(C,G));

ans=(T*T)+(C*C)+(G*G)+(seven*7);

System.out.println(ans);

}

}

Apaxiaaaaaaaaaaaans! Kattis Problem Solution In Java

//Nayeem Shahriar Joy,Applied Physics & Electronic Engineering, University of Rajshahi.
 

import java.util.HashSet;

import java.util.Scanner;

import java.util.Set;

import javax.swing.text.html.HTMLDocument.Iterator;

public class Joy{

public static void main(String[] args) {

Scanner io = new Scanner(System.in);

String s=io.nextLine();

int i;

for( i=0;i<s.length()-1;i++)

{

if(s.charAt(i)!=s.charAt(i+1))

{

System.out.print(s.charAt(i));

}

}

System.out.print(s.charAt(i));

System.out.println();

}

}

Cryptographer's Conundrum Kattis Problem Solution In Java

//Nayeem Shahriar Joy,Applied Physics & Electronic Engineering, University of Rajshahi.
 

import java.util.HashSet;

import java.util.Scanner;

import java.util.Set;

import javax.swing.text.html.HTMLDocument.Iterator; 

 

public class Joy{

public static void main(String[] args) {

Scanner io = new Scanner(System.in);

String s=io.nextLine();

int count=0;

for(int i=0;i<s.length();i++) {

if(!((i%3==0&&s.charAt(i)=='P')||(i%3==1&&s.charAt(i)=='E')||(i%3==2&&s.charAt(i)=='R')))

{

count++;

}

}

System.out.println(count);

}

}

Speed Limit Kattis Problem Solution In Java

import java.util.ArrayList;

import java.util.HashSet;

import java.util.Scanner;

import java.util.Set;

import javax.swing.text.html.HTMLDocument.Iterator;

public class Joy{

public static void main(String[] args) {

// Get input from the user w/ sentinel logic

Scanner reader = new Scanner(System.in);

int pairs = Integer.parseInt(reader.nextLine());

// Keep track of distances

ArrayList<Integer> distances = new ArrayList<Integer>();

while(pairs != -1){ // While still accepting input

int distance = 0;

int hours = 0;

for(int i = 0; i < pairs; i++){

String[] temp = reader.nextLine().split(" "); // Put input into a string

distance += Integer.parseInt(temp[0]) * (Integer.parseInt(temp[1]) - hours); // distance is mph times new hours - old hours

hours = Integer.parseInt(temp[1]); // keep track of current hours

}

distances.add(distance);

pairs = Integer.parseInt(reader.nextLine());

} // end while loop

// Output data to the user

for(int i = 0; i < distances.size(); i++){

System.out.println(distances.get(i) + " miles");

}

// Closed the reader

reader.close();

}// end main

}

Pet Kattis Problem Solution In Java

//Nayeem Shahriar Joy,Applied Physics & Electronic Engineering, University of Rajshahi.

 

import java.util.ArrayList;

import java.util.HashSet;

import java.util.Scanner;

import java.util.Set;

import javax.swing.text.html.HTMLDocument.Iterator; 

 

public class Joy{

public static void main(String[] args) {

// Get input from the user w/ sentinel logic

Scanner io = new Scanner(System.in);

int index=0;

int sum=0,sum1 = 0;

for(int i=1;i<=5;i++)

{

int a=io.nextInt();

int b=io.nextInt();

int c=io.nextInt();

int d=io.nextInt();

sum=a+b+c+d;

if(sum1<=sum)

{

sum1=sum;

index=i;

}

}

System.out.println(index+" "+sum1);

}

}

Modulo Kattis Problem Solution In Java

//Nayeem Shahriar Joy,Applied Physics & Electronic Engineering, University of Rajshahi.
 

import java.util.HashSet;

import java.util.Scanner;

import java.util.Set; 

 

public class Joy{

public static void main(String[] args) {

// Get input from the user w/ sentinel logic

Scanner io = new Scanner(System.in);

Set<Integer>s=new HashSet<Integer>();

for(int i=1;i<=10;i++)

{

int a=io.nextInt();

s.add(a%42);

}

System.out.println(s.size());

}

}

A Real Challenge Kattis Problem Solution In Java

//Nayeem Shahriar Joy,Applied Physics & Electronic Engineering, University of Rajshahi.

 

import java.util.HashSet;

import java.util.Scanner;

import java.util.Set; 

public class Joy{

public static void main(String[] args) {

// Get input from the user w/ sentinel logic

Scanner io = new Scanner(System.in);

double a = io.nextDouble();

System.out.println(4*Math.sqrt(a));

}

}

Mixed Fractions Kattis Problem Solution In Java

//Nayeem Shahriar Joy,Applied Physics & Electronic Engineering, University of Rajshahi.
 

import java.util.ArrayList;

import java.util.HashSet;

import java.util.Scanner;

import java.util.Set; 

 

public class Joy{

public static void main(String[] args) {

// Get input from the user w/ sentinel logic

Scanner in = new Scanner(System.in);

String s=in.nextLine();

String[]values=s.split(" ");

int a=Integer.parseInt(values[0]);

int b=Integer.parseInt(values[1]);

ArrayList<String>answers=new ArrayList<String>();

while(!(s.trim().equals("0 0")))

{

String[] mixedFunction=s.split(" ");

int A=Integer.parseInt(mixedFunction[0]);

int B=Integer.parseInt(mixedFunction[1]);

int frac=A/B;

int num=A%B;

answers.add(""+frac+" "+num+" / "+B);

s=in.nextLine();

}

for(int i=0;i<answers.size();i++)

{

System.out.println(answers.get(i));

}

}

}

One Chicken Per Person! Kattis Problem Solution In Java

//Nayeem Shahriar Joy,Applied Physics & Electronic Engineering, University of Rajshahi.

import java.util.ArrayList;

import java.util.HashSet;

import java.util.Scanner;

import java.util.Set;

public class Joy{

public static void main(String[] args) {

// Get input from the user w/ sentinel logic

Scanner in = new Scanner(System.in);

String s=in.nextLine();

String[]values=s.split(" ");

int a=Integer.parseInt(values[0]);

int b=Integer.parseInt(values[1]);

if(a<b&&(b-a)!=1)

{

System.out.println("Dr. Chaz will have "+(b-a)+" pieces of chicken left over!");

}

else if(a<b&&(b-a)==1)

{

System.out.println("Dr. Chaz will have "+(b-a)+" piece of chicken left over!");

}

else if(a>b&&(a-b)!=1)

{

System.out.println("Dr. Chaz needs "+(a-b)+" more pieces of chicken!");

}

else if(a>b&&(a-b)==1)

{

System.out.println("Dr. Chaz needs "+(a-b)+" more piece of chicken!");

}

}

}

Line Them Up Kattis Problem Solution In Java

//Nayeem Shahriar Joy,Applied Physics & Electronic Engineering, University of Rajshahi.
 

import java.util.ArrayList;

import java.util.HashSet;

import java.util.Scanner;

import java.util.Set; 

 

public class Joy{

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

int a=Integer.parseInt(in.nextLine());

ArrayList<String>s1=new ArrayList<String>();

for(int i=0;i<a;i++)

{

String s=in.nextLine();

s1.add(s);

}

boolean decreasing=false;

boolean increasing=false;

for(int j=0;j<s1.size()-1;j++)

{

if(s1.get(j).compareTo(s1.get(j+1))<0)

{

decreasing=true;

}

else

{

increasing=true;

}

}

if(increasing&&decreasing)

{

System.out.println("NEITHER");

}

else if(!increasing)

{

System.out.println("INCREASING");

}

else

{

System.out.println("DECREASING");

}

}

}

Server Kattis Problem Solution In Java

//Nayeem Shahriar Joy,Applied Physics & Electronic Engineering, University of Rajshahi.
 

import java.util.ArrayList;

import java.util.HashSet;

import java.util.Scanner;

import java.util.Set; 

 

public class Joy{

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

int i=0;

String s=in.nextLine();

String[]values=s.split(" ");

int a=Integer.parseInt(values[1]);

String d=in.nextLine();

String[]joy=d.split(" ");

int sum=0;

int count=0;

for( i=0;i<joy.length;i++)

{

int b=Integer.parseInt(joy[i]);

a=a-b;

if(a>=0) {

count++;

}

else

{

break;

}

}

System.out.println(count);

}

}

Tarifa Kattis Problem Solution In Java

//Nayeem Shahriar Joy, Applied Physics & Electronic Engineering, University of Rajshahi.

import java.util.Scanner;

public class JavaApplication1 {

/**

* @param args the command line arguments

*/

public static void main(String[] args) {

Scanner io=new Scanner(System.in);

int n=io.nextInt();

int x=io.nextInt();

int sum=0;

for(int i=0;i<x;i++)

{

int m=io.nextInt();

sum=sum+m;

}

System.out.println((n*(x+1)-sum));

// TODO code application logic here

}

}

Autori Kattis Problem Solution In Java

//Nayeem Shahriar Joy, Applied Physics & Electronic Engineering, University of Rajshahi.

import java.util.Scanner;

public class JavaApplication1 {

public static void main(String[] args) {

Scanner io=new Scanner(System.in);

String s=io.nextLine();

String[]values=s.split("-");

for(int i=0;i<values.length;i++)

{

System.out.print(values[i].charAt(0));

}

System.out.println();

// TODO code application logic here

}

}

Cetvrta Kattis Problem Solution In Java

//Nayeem Shahriar Joy, Applied Physics & Electronic Engineering, University of Rajshahi.

import java.util.Scanner;

public class JavaApplication1 {

/**

* @param args the command line arguments

*/

public static void main(String[] args) {

Scanner io=new Scanner(System.in);

String s1=io.nextLine();

String s2=io.nextLine();

String s3=io.nextLine();

String[]values1=s1.split(" ");

String[]values2=s2.split(" ");

String[]values3=s3.split(" ");

int A1,B1,A2,B2,A3,B3,A4=0,B4=0;

A1=Integer.parseInt(values1[0]);

B1=Integer.parseInt(values1[1]);

A2=Integer.parseInt(values2[0]);

B2=Integer.parseInt(values2[1]);

A3=Integer.parseInt(values3[0]);

B3=Integer.parseInt(values3[1]);

if(A1==A2)

{

if(B3==B2)

{

A4=A3;

B4=B1;

}

else

{

A4=A3;

B4=B2;

}

}

else if(A2==A3)

{

if(B1==B2)

{

A4=A1;

B4=B3;

}

else

{

A4=A1;

B4=B2;

}

}

else if(A1==A3)

{

if(B2==B3)

{

A4=A2;

B4=B1;

}

else

{

A4=A2;

B4=B3;

}

}

System.out.println(A4+" "+B4);

// TODO code application logic here

}

}