11455 - Behold my quadrangle Uva Solution & Logic

//

*Say , Four Lengths Are  a , b , c , d

* if(a==b &&b==c && c==d &&a==d)  then square

* if( (a==c && b==d)||(a==b && c==d)||(b==c && a==d)) then rectangular 

* if it is not a square & rectangular , then by satisfying the condition 
a<=b+c+d  && b<=a+c+d && c<=b+c+d   it can be  quadrangle

////


Now Code .......................



#include<bits/stdc++.h>

// Nayeem Shahriar Joy , Applied Physics & Electronic Engineering , University of Rajshahi.

using namespace std;


int main()
{
    long long int a, b, c, d;
    int i, t;
    while((scanf("%d", &t)==1))
    {
        for(i=1; i<=t; i++)
        {
            scanf("%lld %lld %lld %lld", &a, &b, &c, &d);
            if(a==b && b==c && c==d) printf("square\n");
            else if( (a==b && c==d) || (b==c && d==a) || (a==c&& b==d)) printf("rectangle\n");
            else if((a<=b+c+d) && (b<=c+d+a) && (c<=d+a+b) && (d<=a+b+c) ) printf("quadrangle\n");
            else printf("banana\n");
        }
    }
}